Wisconsin Is Home To The Four Drunkest Cities In America

Photo: Miami Herald (Getty)

Well to be fair, there is nothing else to do there except watch the Packers, listen to great live music and fish. And even then, you’re crushing brews while doing all three of those.

According to WTMJ-TV, Wisconsin “dominated” a recent list released by 24/7 Wall St. of the drunkest cities in America, as the top four and 12 of the top 20 drunkest cities in the country reside within the borders of the “Land of Cheese and Beer Farts.”

Wisconsin Is Home To The Four Drunkest Cities In America

Almost one out of every four adults in America’s Dairyland say they have an excessive drinking habit, and that’s also tops in the nation.

Appleton took home the award for the drunkest city in America thanks to the fact that it’s home to the “largest share of binge and heavy drinkers in all of America,” as 26.8 percent of adults there binge drink on a regular basis.

While 18 percent of Americans say they drink excessively, 26 percent of the adults in Oshkosh and Neenah say that’s also how they do it, and that’s why they came in second place on the list. They were followed by Green Bay, where 47.5 percent of driving deaths are related to the sauce, and the state capital of Madison, where 25.5 percent of adults binge drink while watching Bucky try to run the ball into the end zone.

The other Wisconsin cities to make the list were La Crosse-Onalaska (#6), Fond du Lac (#7), Eau Claire (#9), Wausau (#11), Sheboygan (#12), Racine (#15), Janesville-Beloit (#16) and Milwaukee-Waukesha-West Allis (#17).

The folks in “Stallis” shouldn’t be too upset about finishing so low on the list though, as we’re sure that somewhere out there they are topping some kind of list involving meth use.

Odds are some of these came out of the Badger State: The Drunkest Texts You Will Ever Read